Acetophenone xrightarrow{{HCO_3H}} A xrightar | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) $1$. $Acetophenone$ $(C_6H_5COCH_3)$ undergoes $Baeyer-Villiger$ oxidation with peroxy acid $(HCO_3H)$ to form phenyl acetate ($A$,$C_6H_5OCOCH_3$

Vedclass · Accepted Answer

$	ext{PhOH} 	ext{ & } 	ext{Phenolphthalein}$

Vedclass · Answer

(C) $1$. $Acetophenone$ $(C_6H_5COCH_3)$ undergoes $Baeyer-Villiger$ oxidation with peroxy acid $(HCO_3H)$ to form phenyl acetate ($A$,$C_6H_5OCOCH_3$).$2$. Acid-catalyzed hydrolysis $(H_3O^{+})$ of phenyl acetate yields phenol ($C$,$C_6H_5OH$) and acetic acid ($B$,$CH_3COOH$).$3$. Phenol $(C)$ reacts with phthalic anhydride in the presence of $H^{+}$ to form phenolphthalein $(D)$,which acts as an indicator.$4$. Thus,$C$ is phenol $(PhOH)$ and $D$ is phenolphthalein.

$Acetophenone$ $\xrightarrow{{HCO_3H}} A$ $\xrightarrow{{H_3O^{+}}} B + C$ $\mathop {\xrightarrow{{Phthalic \, Anhydride}}}\limits_{{H^{+}}} $ Indicator $(D)$
$C$ and $D$ are

Similar Questions

$C_6H_5OH \xrightarrow{CH_3COCl / NaOH_{(aq)}} C_6H_5OCOCH_3$
The above reaction is an example of which of the following?

The major product in the following reaction is:

The major reason that phenol is a better Bronsted acid than cyclohexanol is that

Which among the following has the highest melting point?

Which of the following reacts with diazonium salts to form dyes?

Vedclass Test Series

Exam Paper Generator

Online Exam Module

$Acetophenone$ $\xrightarrow{{HCO_3H}} A$ $\xrightarrow{{H_3O^{+}}} B + C$ $\mathop {\xrightarrow{{Phthalic \, Anhydride}}}\limits_{{H^{+}}} $ Indicator $(D)$$C$ and $D$ are